Эх сурвалжийг харах

Merge branch 'master' of https://github.com/noahvogt/gkg

Simon Hammer 4 жил өмнө
parent
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79271a7f19

+ 17 - 3
protokoll-kondensator/main.tex

@@ -102,6 +102,7 @@ asdasdasd
 $$ Q_{1} + Q_{2} = Q_{3} \Rightarrow m_{\rm{Eis}} \cdot L_f + m_{\rm{Eis}} \cdot c_{\rm{H_2O}} \cdot \Delta\vartheta_1 = m_{\rm{H_2o}} \cdot c_{\rm{H_2o}} \cdot \Delta\vartheta_2$$ $$ \Rightarrow L_f = \frac{m_{\rm{H2O}} \cdot c_{\rm{H_2o}} \cdot \Delta\vartheta_2 - m_{\rm{Eis}} \cdot c_{\rm{H_2O}} \cdot \Delta\vartheta_1}{m_{\rm{Eis}}}$$
 $$ Q_{1} + Q_{2} = Q_{3} \Rightarrow m_{\rm{Eis}} \cdot L_f + m_{\rm{Eis}} \cdot c_{\rm{H_2O}} \cdot \Delta\vartheta_1 = m_{\rm{H_2o}} \cdot c_{\rm{H_2o}} \cdot \Delta\vartheta_2$$ $$ \Rightarrow L_f = \frac{m_{\rm{H2O}} \cdot c_{\rm{H_2o}} \cdot \Delta\vartheta_2 - m_{\rm{Eis}} \cdot c_{\rm{H_2O}} \cdot \Delta\vartheta_1}{m_{\rm{Eis}}}$$
 
 
 NEUE ERKLÄRUNG DER FORMELN HIER
 NEUE ERKLÄRUNG DER FORMELN HIER
+\newpage
 
 
 $$\frac{Q_1}{C_u} = \frac{Q_2}{C_b} = u'\quad \Rightarrow \quad Q_2 = u' \cdot C_b$$
 $$\frac{Q_1}{C_u} = \frac{Q_2}{C_b} = u'\quad \Rightarrow \quad Q_2 = u' \cdot C_b$$
 
 
@@ -114,7 +115,8 @@ $$C_u = \frac{Q_1}{u'} = \frac{Q_{Total}-Q_2}{u'} = \frac{C_b \cdot u - u' \cdot
 \section{Versuchsaufbau}
 \section{Versuchsaufbau}
 \begin{figure}[H]
 \begin{figure}[H]
 
 
-INSERT IMAGE HERE
+\centering
+\includegraphics[width=.8\textwidth]{media/bennenung.png}
 
 
 \end{figure}
 \end{figure}
 
 
@@ -149,24 +151,36 @@ $$C_u = \frac{C_b \cdot u - u' \cdot C_b}{u'}$$
 
 
 $C_{u_{max}} = \displaystyle{\frac{C_{b_{max}}\cdot u_{1_{max}}-u_{1_{min}}'\cdot C_{b_{min}}}{u_{1_{min}}'}}$\\\\
 $C_{u_{max}} = \displaystyle{\frac{C_{b_{max}}\cdot u_{1_{max}}-u_{1_{min}}'\cdot C_{b_{min}}}{u_{1_{min}}'}}$\\\\
 
 
+$C_{u_{max}} = \displaystyle{\frac{4.385\cdot 10^{-6}\;F\cdot 262.5\;V-175.5\;V\cdot 4.375\cdot 10^{-6}\;F}{175.5\;V}} = 2.184\cdot 10^{-6}\;F$\\\\
+
 $C_{u_{min}} = \displaystyle{\frac{C_{b_{min}}\cdot u_{1_{min}}-u_{1_{max}}'\cdot C_{b_{max}}}{u_{1_{max}}'}}$\\\\
 $C_{u_{min}} = \displaystyle{\frac{C_{b_{min}}\cdot u_{1_{min}}-u_{1_{max}}'\cdot C_{b_{max}}}{u_{1_{max}}'}}$\\\\
 
 
-$\Rightarrow C_{u_1}=\displaystyle{\frac{C_{u_{max}}+C_{u_{min}}}{2}}$
+$C_{u_{min}} = \displaystyle{\frac{4.375\cdot 10^{-6}\;F\cdot 257.5\;V-180.5\;V\cdot 4.385\cdot 10^{-6}\;F}{180.5\;V}} = 1.856\cdot 10^{-6}\;F$\\\\
+
+$\Rightarrow C_{u_1}=\displaystyle{\frac{C_{u_{max}}+C_{u_{min}}}{2}} = 2.02005 (\pm 0.1637)\cdot \mu F$
 
 
 \subsection{Durchführung 2}
 \subsection{Durchführung 2}
 
 
 $C_{u_{max}} = \displaystyle{\frac{C_{b_{max}}\cdot u_{2_{max}}-u_{2_{min}}'\cdot C_{b_{min}}}{u_{2_{min}}'}}$\\\\
 $C_{u_{max}} = \displaystyle{\frac{C_{b_{max}}\cdot u_{2_{max}}-u_{2_{min}}'\cdot C_{b_{min}}}{u_{2_{min}}'}}$\\\\
 
 
+$C_{u_{max}} = \displaystyle{\frac{4.385\cdot 10^{-6}\;F\cdot 302.5\;V-198.5\;V\cdot 4.375\cdot 10^{-6}\;F}{195.5\;V}}$\\\\
+
 $C_{u_{min}} = \displaystyle{\frac{C_{b_{min}}\cdot u_{2_{min}}-u_{2_{max}}'\cdot C_{b_{max}}}{u_{2_{max}}'}}$\\\\
 $C_{u_{min}} = \displaystyle{\frac{C_{b_{min}}\cdot u_{2_{min}}-u_{2_{max}}'\cdot C_{b_{max}}}{u_{2_{max}}'}}$\\\\
 
 
+$C_{u_{min}} = \displaystyle{\frac{4.375\cdot 10^{-6}\;F\cdot 297.5\;V-203.5\;V\cdot 4.385\cdot 10^{-6}\;F}{203.5\;V}}$\\\\
+
 $\Rightarrow C_{u_2}=\displaystyle{\frac{C_{u_{max}}+C_{u_{min}}}{2}}$
 $\Rightarrow C_{u_2}=\displaystyle{\frac{C_{u_{max}}+C_{u_{min}}}{2}}$
 
 
-\subsection{Durchführung 2}
+\subsection{Durchführung 3}
 
 
 $C_{u_{max}} = \displaystyle{\frac{C_{b_{max}}\cdot u_{3_{max}}-u_{3_{min}}'\cdot C_{b_{min}}}{u_{3_{min}}'}}$\\\\
 $C_{u_{max}} = \displaystyle{\frac{C_{b_{max}}\cdot u_{3_{max}}-u_{3_{min}}'\cdot C_{b_{min}}}{u_{3_{min}}'}}$\\\\
 
 
+$C_{u_{max}} = \displaystyle{\frac{4.385\cdot 10^{-6}\;F\cdot 282.5\;V-189.5\;V\cdot 4.375\cdot 10^{-6}\;F}{189.5\;V}}$\\\\
+
 $C_{u_{min}} = \displaystyle{\frac{C_{b_{min}}\cdot u_{3_{min}}-u_{3_{max}}'\cdot C_{b_{max}}}{u_{3_{max}}'}}$\\\\
 $C_{u_{min}} = \displaystyle{\frac{C_{b_{min}}\cdot u_{3_{min}}-u_{3_{max}}'\cdot C_{b_{max}}}{u_{3_{max}}'}}$\\\\
 
 
+$C_{u_{min}} = \displaystyle{\frac{4.375\cdot 10^{-6}\;F\cdot 277.5\;V-194.5\;V\cdot 4.385\cdot 10^{-6}\;F}{194.5\;V}}$\\\\
+
 $\Rightarrow C_{u_3}=\displaystyle{\frac{C_{u_{max}}+C_{u_{min}}}{2}}$
 $\Rightarrow C_{u_3}=\displaystyle{\frac{C_{u_{max}}+C_{u_{min}}}{2}}$
 
 
 \section{Kommentar / Diskussion}
 \section{Kommentar / Diskussion}